Waves & Oscillations · Chapter 11

Interference & Diffraction

Waves add together. Where they add constructively, you get bright spots. Where they cancel, darkness. These patterns encode deep information about sources, slits, and the wave nature of light itself.

PrerequisitesWaveproperties(Ch.8)superposition,wavelength,phaseTrigonometryWave properties (Ch. 8) — superposition, wavelength, phase \cdot Trigonometry
Learning Goals
  • State the superposition principle and express the total displacement of two overlapping waves.
  • Derive the conditions for constructive and destructive interference from path difference.
  • ApplytheYoungsdoubleslitfringespacingformulaym=m\lambdaL/dtocalculatefringepositApply the Young's double-slit fringe spacing formula y_{m} = m\lambdaL/d to calculate fringe positions.
  • Predict how fringe spacing changes with wavelength, slit separation, and screen distance.
  • Explain why single-photon and single-electron double-slit experiments still show interference.

11.1 The Superposition Principle

When two waves overlap in space, the resulting displacement at any point is simply the sum of the individual displacements. This linearity is the superposition principle, and it is what gives rise to interference patterns.

ytotal(x,t)=y1(x,t)+y2(x,t)y_\mathrm{total}(x,t)=y_1(x,t)+y_2(x,t)(11.1)

The superposition principle holds for all linear wave systems — light, sound, water waves, and quantum mechanical probability amplitudes. It breaks down only when the medium responds nonlinearly to large amplitudes (e.g., nonlinear optics, shock waves).

11.2 Two-Source Interference

Two coherent point sources emit identical waves. At any point P in the field, the two waves arrive having traveled different distances r₁ and r₂. The path differenceΔr = |r₂ − r₁| determines whether they interfere constructively or destructively.

Definition 11.1Conditions for Two-Source Interference
Fortwocoherentsourcesinphase(Δϕ=0For two coherent sources in phase (\Delta\phi = 0:
  • Constructive: \Deltar=mλ(m=0,±1,±2,)wavesarriveinphase,amplitudesadd\Deltar = m\lambda \qquad (m = 0, \pm1, \pm2, \cdots) — waves arrive in phase, amplitudes add
  • Destructive: \Deltar=(m+12)λ(m=0,±1,±2,)wavesarriveoutofphase,amplitudescancel\Deltar = (m + \frac{1}{2})\lambda \qquad (m = 0, \pm1, \pm2, \cdots) — waves arrive out of phase, amplitudes cancel
IfthesourceshaveaninitialphaseoffsetΔϕ,replace\Deltar=mλwith\Deltar=mλΔϕ/(2π)λIf the sources have an initial phase offset \Delta\phi, replace \Deltar = m\lambda with \Deltar = m\lambda - \Delta\phi/(2\pi)\lambda.

Each source emits:

y=Asin(krωt+ϕ)k=2πλy=A\sin(kr-\omega t+\phi) \qquad k=\frac{2\pi}{\lambda}(11.2)
Wavelength λ60 px
Source spacing5 × λ
Phase difference Δφ0°
Interference condition
Constructive (Δφ = 0)

Constructive — waves in phase (Δφ = 0, 2π, …) → bright bands

Destructive — waves out of phase (Δφ = π, 3π, …) → dark bands

Blue = positive amplitude, Red = negative amplitude.

The pattern is the 2D superposition: y = y₁ + y₂

Figure 11.1. Twosourceinterferencepattern.Blue=constructiveinterference(wavesinphase),red=Two-source interference pattern. Blue = constructive interference (waves in phase), red = destructive(outofphase),black=nodallines.Adjustsourceseparation,wavelength,anddestructive (out of phase), black = nodal lines. Adjust source separation, wavelength, andphase difference to watch the pattern change.

11.3 Young's Double-Slit Experiment

Thomas Young's 1801 experiment showed that light produces an interference pattern, proving its wave nature. A monochromatic source illuminates two narrow slits separated by distance d. On a screen at distance L (with L ≫ d), bright fringes appear at positions:

ym=mλLdm=0,±1,±2,y_m=\frac{m\lambda L}{d} \qquad m=0,\pm1,\pm2,\ldots(11.3)

where m is the fringe order. The fringe spacing is constant: Δy = λL/d. Shorter wavelength gives closer fringes; larger slit separation also gives closer fringes.

Example 11.1Double-Slit Fringe Spacing

InYoungsexperiment:slitseparationd=0.2mm,screendistanceL=2.0m,wavelengthλIn Young's experiment: slit separation d = 0.2 mm, screen distance L = 2.0 m, wavelength \lambda = 550 nm. Find the fringe spacing and the position of the third bright fringe.

Fringe spacing:\Deltay=\lambdaL/d=(550×109×2.0)/(0.2×103)=\Deltay = \lambdaL/d = (550\times10^{-9} \times 2.0) / (0.2\times10^{-3}) = 5.5 mm
Third fringe (m=3):y3=3×5.5mm=y_{3} = 3 \times 5.5 mm = 16.5 mm from center
Note:Switchingtoλ=440nm(violet):\Deltay=4.4mmfringespackclosertogether.SwitchingtoSwitching to \lambda = 440 nm (violet): \Deltay = 4.4 mm — fringes pack closer together. Switching to d=0.4mm:\Deltay=2.75mmsameeffectd = 0.4 mm: \Deltay = 2.75 mm — same effect

11.4 What to Watch in the Simulation

This experiment is so fundamental that it has been repeated with single photons, electrons, atoms, and even molecules — and it still shows interference. The wave nature is a property of quantum probability amplitudes, not just classical wave superposition.

Definition 11.2Common Traps
  • Constructive does not mean high everywhere: the path difference changes from point to point.
  • Fringe spacing uses consistent units: convertnm,mm,andmbeforeusing\Deltay=\lambdaL/dconvert nm, mm, and m before using \Deltay = \lambdaL/d
  • Increasing slit separation narrows the pattern: \Deltayisinverselyproportionaltod\Deltay is inversely proportional to d
  • Single-particle interference is not particle collision: the interference belongs to probability amplitudes.
Exercises — 11.1–11.4 Interference
1.
InYoungsdoubleslitexperimentwithd=0.2mm,L=2.0m,andλ=550nm,findthefriIn Young's double-slit experiment with d = 0.2 mm, L = 2.0 m, and \lambda = 550 nm, find the fringe spacing.
mm
Straightforward
2.
RepeattheYoungsdoubleslitcalculationwithvioletlight(λ=440nm),samegeometryRepeat the Young's double-slit calculation with violet light (\lambda = 440 nm), same geometry. What is the new fringe spacing?
mm
Straightforward
3.Twocoherentsourcesare4λapart(samefrequency,inphase).FindtheangleofthefirstTwo coherent sources are 4\lambda apart (same frequency, in phase). Find the angle of the first dark fringe.
Intermediate
4.Compare the interference pattern from two slits vs. three equally spaced slits (same spacing d). Where are the principal maxima for three slits? How do intensity and fringe width compare?
Intermediate
5.Derive the intensity pattern for a double slit with finite slit width a and separation d. Explain missing orders and when they occur.
Challenging
Key Takeaways
  • Superposition:ytotal=y1+y2.LinearwavesaddpointwiseSuperposition: y_{total} = y_{1} + y_{2}. Linear waves add pointwise.
  • Constructive:\Deltar=mλ;destructive:\Deltar=(m+12)λ(forinphasesourcesConstructive: \Deltar = m\lambda; destructive: \Deltar = (m+\frac{1}{2})\lambda (for in-phase sources.
  • Youngsfringespacing:\Deltay=\lambdaL/d.SmallerλorlargerdcloserfringesYoung's fringe spacing: \Deltay = \lambdaL/d. Smaller \lambda or larger d \to closer fringes.
  • PhaseoffsetΔϕshiftstheentirepattern180°phaseinvertsconstructiveanddestructivPhase offset \Delta\phi shifts the entire pattern — 180° phase inverts constructive and destructive.
  • Single-particle experiments (photon, electron) reproduce the interference pattern — wave nature is intrinsic to quantum amplitude, not a classical field effect.